国产人妻人伦精品_欧美一区二区三区图_亚洲欧洲久久_日韩美女av在线免费观看

合肥生活安徽新聞合肥交通合肥房產生活服務合肥教育合肥招聘合肥旅游文化藝術合肥美食合肥地圖合肥社保合肥醫院企業服務合肥法律

COMP5930M 代做、代寫 c++,java 程序語言

時間:2023-12-11  來源:合肥網hfw.cc  作者:hfw.cc 我要糾錯



School of Computing: assessment brief
   Module title
 Scientific Computation
  Module code
 COMP5930M
  Assignment title
 Coursework 2
  Assignment type and description
 Coursework assignment
  Rationale
 TBA
  Weighting
 20% of total mark
  Submission dead- line
 December 14th 2023 at 10:00
  Submission method
 Turnitin submission through Minerva
  Feedback provision
 Feedback provided on Minerva
  Learning outcomes assessed
 (i) Formulate and solve systems of nonlinear equations to solve challenging real-world problems arising from en- gineering and computational science; (ii) Implement al- gorithmic solutions to solve computational differential equation problems based on mathematical theory; (iii) Analyse computational linear algebra problems to iden- tify and implement the most efficient and scalable solu- tion algorithm to apply for large problems.
  Module lead
 Dr Toni Lassila
           1

1. Assignment guidance
Provide answers to the two exercises below. Answer both exercises.
2. Assessment tasks
Exercise 1: The Burgers’ equation models the propagation of a pres- sure wave in shock tube. It is a nonlinear partial-differential equation in one spatial dimension to find u(x, t) s.t.
∂u + u∂u = ν ∂2u, (1) ∂t ∂x ∂x2
where the boundary conditions u(a, t) = ua and u(b, t) = ub for all t, and the initial condition u(x, 0) = u0(x) need to be prescribed in order to obtain a well-posed problem. Here ν is the kinematic viscosity of the fluid. For ν = 0 we have the inviscid Burgers’ equation, and for ν > 0 we have the viscous Burgers’ equation.
(a) Applying the central difference formula to the second order deriva- tive in space, the upwind difference formula
􏰀Uk−Uk 􏰁
i−1
using implicit Euler’s method leads to the discrete formulation: Uk −Uk−1 􏰀Uk −Uk 􏰁 􏰀Uk −2Uk +Uk 􏰁
Fi(U)= i i +Uik i i−1 −ν i+1 i i−1 =0 ∆t h h2
(2) for i = 2,3,...,m−1 where the interval has been discretised with
m uniformly distributed nodes and a spatial grid size h. Implement the function F as a python subroutine fun burgers.py
        def fun_burgers( uk, ukp, dt, h, nu, ua, ub )
where uk is the vector Uk of size m, ukp is the previous time-step solution vector Uk−1, dt is the time-step ∆t, h is the spatial grid size parameter h, and nu is the kinematic viscosity ν. Include the boundary conditions ua and ub in the implementation. [6 marks]
2
Uik i
to the first order derivative in space, and discretising (1) in time
 h
   
(b) Derive the analytical formulas for the nonzero elements on row i of the Jacobian matrix for (2): [4 marks]
∂Fi , ∂Fi, ∂Fi . ∂Ui−1 ∂Ui ∂Ui+1
(c) Solve problem (2) numerically using your fun burgers.py and the PDE solver template solver burgers.py provided in the course- work folder. Use the viscosity value ν = 0.01, the time-step ∆t=0.01,thegridsizeh=0.01,andafinaltimeofT =1. The initial solution u(x, 0) should be taken as a unit step located at x = 0.1 (see below) and the boundary conditions as: u(0, t) = 1 and u(1, t) = 0.
   Figure 1: Initial condition u0(x) for the Burgers’ equation (1)
Plot the solution u(x, T ) at the final time step T = 1 and include it in your report. Also report the total number of Newton iterations required for the numerical solution (sum of Newton iterations over all time steps). [2 marks]
3

(d) The solution of Burgers’ equation (1) can be shown to be a (decay- ing) wavefront that travels from left to right at a constant velocity v. What is the approximate value of the numerical wavefront ve- locity vnum for ν = 0.01, ∆t = 0.01, and h = 0.01? Measure the approximate location of the wavefront using the point where the solution u(xmid) ≈ 0.5. [1 mark]
(e) Replace the discretisation of the nonlinear convection term with the downwind difference formula
􏰀Uk − Uk 􏰁
i (3)
and solve the problem with same parameters as in (c). Plot the solution u(x,T) at the final time step T = 1 and include it in your report. Also report the total number of Newton iterations required for the numerical solution (sum of Newton iterations over all time steps). What is the numerical wavefront velocity vnum in this case?
Now set ν = 0.001 and solve the problem again using the down- wind difference formula. What do you observe? Now solve the problem with ν = 0.001 using the original upwind difference for- mula and compare the results. What is the numerical wavefront velocity vnum in this case? [7 marks]
Uik i+1
h
 4

Exercise 2: Consider the anisotropic diffusion equation to find u(x, y) s.t.
􏰀 ∂2u ∂2u􏰁
− μx∂x2 +μy∂y2 =f(x,y), (x,y)∈(0,1)×(0,1), (4)
and the boundary condition u = 0 on Γ (the boundary of the unit square), where u is a scalar function that models the temperature of a heat-conducting object modelled here as a unit square and f(x,y) is a function modelling a heat source. The heat conductivity coefficients, μx > 0 and μy > 0, can have different magnitudes (anisotropy).
(a) Discretising the problem (4) using the second-order finite differ- ence formulas
∂2u ≈ ui,j−1 − 2ui,j + ui,j+1 .
Write the second-order finite difference stencil (similarly as in Tu- torial 7)
∂2u ≈ ui−1,j − 2ui,j + ui+1,j , ∂x2 h2
  ∂y2
−μx h2 −μy h2 = fi,j.
h2 􏰀ui−1,j − 2ui,j + ui+1,j 􏰁 􏰀ui,j−1 − 2ui,j + ui,j+1 􏰁
leads to the discretised form
  ?**7;
s11 s12 s13 ?**8; ?**8;
S=s s s?**8;  21 22 23?**8;
?**8; s s s?**9;
corresponding to this finite difference scheme. [4 marks] (b) Implement a python function source function.py
    def source_function( x, y, h )
that returns the right-hand side by evaluating the function:
f(x,y) :=
⭺**;1, ifx≥0.1andx≤0.3andy≥0.1andy≤0.3 0, otherwise
.
Include the source code in your answer. [3 marks] 5
31 ** 33
(5)

 Figure 2: Computational domain for problem (4) and the sub-region where the heat source is located (in red).
(c) Modify the solver from Tutorial 7 to numerically solve the diffusion problem (4) for the right-hand side (5).
Solve the linear problem AU = F using the conjugate gradient method (without preconditioning) with the diffusion coefficients μx = 1 and μy = 1, stopping tolerance tol = 10−6, and maxi- mum of 1000 CG iterations. You can use the CG implementation in scipy.sparse.linalg.cg for this problem or code your own implementation.
Plot the solution surface and include the plot in your answer. How many iterations does it take for CG to converge in this case?
[2 marks]
(d) Consider now the use of a preconditioner to accelerate the con- vergence of CG. The incomplete-LU preconditioner approximates the system matrix A ≈ LincUinc by performing Gaussian elimi- nation but setting to zero any elements that are smaller than a dropoff tolerance ε chosen by the user. You can use the imple- mentation provided in scipy.sparse.linalg.spilu to compute
6

the incomplete factors Linc and Uinc.
Write a python implementation myPCG.py of the preconditioned
conjugate gradient from Lecture 18:
            def myPCG( A, b, L, U, tol, maxit )
that solves the preconditioning step for the residual, Mzi+1 = LU zi+1 = ri+1 , using appropriate solution algorithms. Include the source code as part of your answer. [4 marks]
(e) Solve the problem (4) again using your preconditioned CG imple- mentation from (d). Use a dropout tolerance of ε = 0.1 for the incomplete LU-factorisation.
How many nonzero elements (nnz) do the factors Linc and Uinc have in this case?
How many PCG iterations does the problem take to converge to tol = 10−6 now?
[2 marks]
(f) Repeat the experiment from (e) with different values of the dif- fusion coefficients. Solve the problem (4) with μx = 0.1 and μx = 0.01, while keeping the other value at μy = 1. Solve the problem using PCG with the same ILU-preconditioner as before with a dropout tolerance of ε = 0.1. Plot the two respective solu- tions and the respective number of CG iterations. What do you observe?
[5 marks]
3. General guidance and study support
The MS Teams group for COMP53**M Scientific Computation will be used for general support for this assignment. If your question would reveal parts of the answer to any problem, please send a private message to the module leader on MS Teams instead. You can also use the tutorial sessions to ask questions about coursework.
4. Assessment criteria and marking process
Assessment marks and feedback will be available on Minerva within
three weeks of the submission deadline. Late submissions are allowed 7

within 14 days of the original deadline providing that a request for an extension is submitted before the deadline. Standard late penalties apply for submissions without approved extensions.
5. Presentation and referencing
When writing mathematical formulas, use similar notation and sym- bols as during the lectures and tutorials. Hand-written sections for mathematical notation are acceptable but need to be clearly readable.
You may assume theorems and other results that have been presented during lectures and tutorials as known. Any other theorems need to be cited using standard citation practice.
6. Submission requirements
This is an individual piece of work. Submit your answers through Tur- nitin as one PDF document (generated either in Word or with LaTeX). You may use hand-written and scanned pages for mathematical formu- las, but these need to be clearly legible and the document must contain at least some typeset text or Turnitin will reject it. All submissions will be checked for academic integrity.
7. Academic misconduct and plagiarism
Academic integrity means engaging in good academic practice. This involves essential academic skills, such as keeping track of where you find ideas and information and referencing these accurately in your work.
By submitting this assignment you are confirming that the work is a true expression of your own work and ideas and that you have given credit to others where their work has contributed to yours.
8. Assessment/marking criteria grid
Total number of marks is 40, divided as follows:
Exercise 1 (One-dimensional Burgers equation): 20 marks
Exercise 2 (Anisotropic diffusion and conjugate gradient): 20 marks
請加QQ:99515681 或郵箱:99515681@qq.com   WX:codehelp

掃一掃在手機打開當前頁
  • 上一篇:CAN201 代做、代寫 Python語言編程
  • 下一篇:代寫COM6471、代做 java 語言編程
  • 無相關信息
    合肥生活資訊

    合肥圖文信息
    流體仿真外包多少錢_專業CFD分析代做_友商科技CAE仿真
    流體仿真外包多少錢_專業CFD分析代做_友商科
    CAE仿真分析代做公司 CFD流體仿真服務 管路流場仿真外包
    CAE仿真分析代做公司 CFD流體仿真服務 管路
    流體CFD仿真分析_代做咨詢服務_Fluent 仿真技術服務
    流體CFD仿真分析_代做咨詢服務_Fluent 仿真
    結構仿真分析服務_CAE代做咨詢外包_剛強度疲勞振動
    結構仿真分析服務_CAE代做咨詢外包_剛強度疲
    流體cfd仿真分析服務 7類仿真分析代做服務40個行業
    流體cfd仿真分析服務 7類仿真分析代做服務4
    超全面的拼多多電商運營技巧,多多開團助手,多多出評軟件徽y1698861
    超全面的拼多多電商運營技巧,多多開團助手
    CAE有限元仿真分析團隊,2026仿真代做咨詢服務平臺
    CAE有限元仿真分析團隊,2026仿真代做咨詢服
    釘釘簽到打卡位置修改神器,2026怎么修改定位在范圍內
    釘釘簽到打卡位置修改神器,2026怎么修改定
  • 短信驗證碼 寵物飼養 十大衛浴品牌排行 suno 豆包網頁版入口 目錄網 排行網

    關于我們 | 打賞支持 | 廣告服務 | 聯系我們 | 網站地圖 | 免責聲明 | 幫助中心 | 友情鏈接 |

    Copyright © 2025 hfw.cc Inc. All Rights Reserved. 合肥網 版權所有
    ICP備06013414號-3 公安備 42010502001045

    国产人妻人伦精品_欧美一区二区三区图_亚洲欧洲久久_日韩美女av在线免费观看
    欧美理论一区二区| 午夜精品久久久久久久久久久久 | 91九色单男在线观看| 国产精品久久久久久搜索| 日本a级片电影一区二区| 91成人福利在线| 亚洲v日韩v欧美v综合| 国产精品一区二区三区免费观看 | 久久免费精品日本久久中文字幕| 国产精品国产自产拍高清av水多| 欧美精品一区二区性色a+v| 日韩一区二区欧美| 青青视频在线播放| 久久久国产影院| 欧美成人综合一区| 国产精品日韩在线| 欧美区高清在线| 久久久91精品国产一区不卡| 欧美一级大胆视频| 久久久国产视频| 欧美专区第一页| 日韩中文字幕在线视频播放| 欧美日韩系列| 国产精品日韩在线观看| 免费观看美女裸体网站| 精品国产综合区久久久久久| 成人免费视频91| 视频一区二区在线| 日韩亚洲一区二区| 免费无遮挡无码永久视频| 国产精品精品一区二区三区午夜版| 激情一区二区三区| 国产精品福利观看| 国产精品夜间视频香蕉| 亚洲一区二三| 91精品国产高清自在线| 欧美一级免费看| 日韩一区二区在线视频| 美媛馆国产精品一区二区| 国产aaa一级片| 久久久日本电影| 欧美在线日韩精品| 精品国产91亚洲一区二区三区www| 国产乱码精品一区二区三区不卡| 亚洲一区亚洲二区| 久久久久免费精品| 免费黄色福利视频| 亚洲人成网站在线播放2019| 国产不卡av在线免费观看| 精品欧美一区免费观看α√| 另类美女黄大片| 91精品视频大全| 日韩免费在线观看视频| 国产精品麻豆免费版| 俄罗斯精品一区二区三区| 日韩国产欧美精品| 精品国产乱码久久久久久郑州公司| 91国视频在线| 国内成人精品一区| 视频一区国产精品| 国产精品久久久久高潮| 久久久人人爽| 国产三级中文字幕| 日韩欧美在线播放视频| 欧美激情xxxx性bbbb| 久久综合狠狠综合久久综青草| 黄色国产精品视频| 亚洲欧洲精品一区二区三区波多野1战4| 国产成人精品999| 国产欧美日韩综合一区在线观看| 日本高清一区| 亚洲自拍欧美另类| 国产精品女人网站| 国产成人一区二区三区电影| 国产女人精品视频| 欧美精彩一区二区三区| 色狠狠久久av五月综合|| 久久国产精品久久久久久久久久| 久久久久久久久影视| 成人免费观看cn| 欧美久久久久久久久久久久久久| 亚洲精品欧美一区二区三区| 操91在线视频| 国产成人免费av| 久久天堂国产精品| 国产日韩中文在线| 欧美日韩国产精品一卡| 午夜精品免费视频| 一区二区三区免费看| 久久精品亚洲一区| 国产成人短视频| 成年人网站国产| 精品一区国产| 免费中文日韩| 欧美又大粗又爽又黄大片视频| 亚洲三级一区| 国产99在线播放| 国产精品第8页| 久青草国产97香蕉在线视频| 国产成人黄色av| 久久天堂国产精品| 68精品久久久久久欧美| 成人黄色av网站| 国产精品中文久久久久久久| 国内精品免费午夜毛片| 欧美精品在欧美一区二区| 日韩欧美亚洲精品| 日本精品福利视频| 天天综合色天天综合色hd| 亚洲欧洲一区二区在线观看| 久久五月天色综合| 国产精品热视频| 国产精品色悠悠| 久久精品人人做人人爽| 日韩视频一区在线| 久久久国产成人精品| 久久精品视频中文字幕| 国产精品免费久久久| 国产精品久久久久久久久| 国产精品久久一区| 久久伊人精品视频| 久久夜色精品国产亚洲aⅴ| 国产精品久久av| 欧美成人免费va影院高清| 九色精品免费永久在线| 欧美日韩aaaa| 欧美激情在线有限公司| 伊人久久婷婷色综合98网| 亚洲影视中文字幕| 日日碰狠狠丁香久燥| 日韩欧美黄色大片| 激情小视频网站| 国产欧美一区二区三区在线看| 粉嫩精品一区二区三区在线观看| 成人av在线亚洲| 久久人人爽人人爽人人av| 久久99精品久久久久久秒播放器 | 99在线影院| 7777精品久久久久久| 国产不卡一区二区在线播放| 色偷偷88888欧美精品久久久| 久久天堂电影网| 久久99精品视频一区97| 一本—道久久a久久精品蜜桃| 亚洲国产一区二区精品视频| 欧美一级黄色影院| 欧美日韩亚洲一区二区三区四区| 精品午夜一区二区| www.日本少妇| 久久久久五月天| 欧美成人精品三级在线观看| 亚洲黄色一区二区三区| 青青草视频国产| 国产原创欧美精品| av一区二区三区在线观看| 久久精品国产一区二区三区不卡 | 欧美综合77777色婷婷| 蜜桃视频一区二区在线观看| 福利视频一区二区三区四区| 国产成人在线播放| 成人444kkkk在线观看| 亚洲欧美日韩不卡| 欧美日韩黄色一级片| 国产精品自拍合集| 久久免费视频在线| 国产成人免费高清视频| 中文字幕日韩精品久久| 日韩精品视频在线观看视频| 国产欧美在线看| 日韩有码视频在线| 欧美激情一区二区三区久久久| 日韩av在线一区二区三区| 狠狠色综合色区| 91精品久久久久久久久久久久久久| 精品国偷自产在线| 亚洲国产激情一区二区三区| 欧美精品成人网| 911国产网站尤物在线观看| 国产精品久久久久久久一区探花 | 91福利视频在线观看| 国产精品极品美女粉嫩高清在线| 亚洲a区在线视频| 国产在线视频不卡| www.国产精品一二区| 亚洲va久久久噜噜噜久久狠狠| 国内一区二区三区在线视频| 久久久久高清| 亚洲午夜精品福利| 欧美第一黄网| 国产福利精品视频| 一区不卡字幕| 精品一区二区三区无码视频| 久久久久久久久国产精品| 一区二区三视频| 国内精品久久久久久影视8 | 国产男女免费视频| 久久久精品国产网站| 日本欧美一二三区| 91美女福利视频高清| 精品久久蜜桃|